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Engineering guide

The MIFL module calculates the adiabatic mixing of two humid air streams – a fundamental task in HVAC and drying technology. From the mass flow, temperature, total pressure and relative humidity of both streams, the module determines the state of the mixed air stream: mixing temperature, humidity ratio (moisture content), relative humidity, specific enthalpy and density of the humid air.

This calculation is needed wherever air streams are combined: for recirculated-air mixing in air-handling systems, for mixing fresh and exhaust air in dryers, for blending in humidified air, or for assessing whether a mixture enters the fog region and condensate forms. The evaluation follows the classic Mollier h-x methodology: the states are described via the partial pressure and saturation pressure of the water vapour, the humidity ratio x and the specific enthalpy h; the mixing point lies on the straight line connecting the initial states in the h-x diagram.

Anyone who wants to calculate the mixing temperature of humid air or determine the relative humidity after mixing thus obtains a closed-form balance calculation without graphical reading – including the split of the mass flows into dry air, vapour and, where applicable, liquid water.

Allgemein · Thermodynamik

Scope

  • Mixing of two humid air streams

Typical workflow

  1. Determine the states of the individual streams

    For both air streams, the saturation pressure and the partial pressure of the water are calculated from temperature, total pressure and relative humidity; from these follow the humidity ratio x (kg of water per kg of dry air), the humidity ratio at saturation, the specific enthalpy and the density of the humid air.

  2. Split the mass flows

    Each humid air mass flow is split into its dry-air fraction and its water fraction (vapour, possibly liquid), because the mixing balances are referred to the dry air – it is the conserved quantity of the calculation.

  3. Set up the mixing balances

    The dry-air mass balance, the water balance and the enthalpy balance yield the humidity ratio and specific enthalpy of the mixed stream; in the h-x diagram, this corresponds to the mixing point on the straight line between the two initial states, divided in the ratio of the dry-air mass flows.

  4. Evaluate mixing temperature and relative humidity

    From the enthalpy and humidity ratio of the mixed stream, the mixing temperature is calculated; with the partial pressure of the water and the saturation pressure at the mixing temperature, the relative humidity of the mixture follows.

  5. Check the fog region

    If the humidity ratio of the mixture exceeds the saturation humidity ratio at the mixing temperature, liquid water precipitates (fog); the water fraction is then split into saturated vapour and liquid water.

Frequently asked questions

Why are the balances referred to the dry-air mass and not to the humid air?

The dry-air mass remains constant during humidification, dehumidification and mixing – the total humid mass does not. This is why the humidity ratio x and the specific enthalpy h are consistently referred to 1 kg of dry air; only then do the balances become linear and the mixing point lies exactly on the straight line in the h-x diagram.

Can fog form when two unsaturated air streams are mixed?

Yes. The saturation line in the h-x diagram is curved; the mixing line between two states close to saturation can therefore cut into the fog region. A classic example is visible breath in winter: each stream on its own is unsaturated, yet the mixture is supersaturated and water condenses out.

Is the mixing temperature the mass-weighted average of the inlet temperatures?

Only approximately. Strictly, it is the specific enthalpy (referred to dry air) that is averaged, not the temperature. Since the heat capacity of humid air depends on the water content, the actual mixing temperature deviates from the simple temperature average – by several tenths of a degree up to a degree for strongly differing humidities.

What role does the total pressure play?

The humidity ratio depends directly on the total pressure via x = 0.622·pD/(p − pD): the same relative humidity means a higher moisture content at lower pressure. Mixing calculations for high-altitude locations or pressurised systems must therefore be carried out with the actual total pressure, not with standard pressure.

Worked example

In a ventilation system, 1.0 kg/s of humid air at 20 °C and 40 % relative humidity is mixed adiabatically with 0.5 kg/s of humid air at 40 °C and 80 % relative humidity. The total pressure is 1.0 bar. Find the humidity ratio, temperature and relative humidity of the mixture – a worked example of mixing two humid air streams.

Given

Mass flow humid air 11.0 kg/s
Temperature / rel. humidity stream 120 °C / 40 %
Mass flow humid air 20.5 kg/s
Temperature / rel. humidity stream 240 °C / 80 %
Total pressure p1.0 bar (100,000 Pa)

Solution

Humidity ratios of the individual streams

Saturation pressures from the Magnus formula: ps(20 °C) ≈ 2,333 Pa, ps(40 °C) ≈ 7,367 Pa.
Partial pressures: pD1 = 0.40 · 2,333 = 933 Pa; pD2 = 0.80 · 7,367 = 5,894 Pa.
x = 0.622 · pD/(p − pD):
x1 = 0.622 · 933/99,067 = 0.00586 kg/kg; x2 = 0.622 · 5,894/94,106 = 0.0390 kg/kg.

Dry-air mass flows and enthalpies

ṁL1 = 1.0/(1 + x1) = 0.9942 kg/s; ṁL2 = 0.5/(1 + x2) = 0.4813 kg/s.
h = 1.005·t + x·(2,501 + 1.86·t) kJ/kg dry air:
h1 = 1.005 · 20 + 0.00586 · (2,501 + 37.2) = 35.0 kJ/kg
h2 = 1.005 · 40 + 0.0390 · (2,501 + 74.4) = 140.5 kJ/kg

Mixing balances

Water balance: xM = (ṁL1·x1 + ṁL2·x2)/(ṁL1 + ṁL2) = (0.9942 · 0.00586 + 0.4813 · 0.0390)/1.4754 = 0.0167 kg/kg.
Enthalpy balance: hM = (0.9942 · 35.0 + 0.4813 · 140.5)/1.4754 = 69.4 kJ/kg.

Mixing temperature and relative humidity

From hM = 1.005·tM + xM·(2,501 + 1.86·tM) it follows that:
tM = (69.4 − 0.0167 · 2,501)/(1.005 + 0.0167 · 1.86) = 26.8 °C.
Partial pressure: pDM = p·xM/(0.622 + xM) = 2,608 Pa; ps(26.8 °C) ≈ 3,512 Pa.
φM = 2,608/3,512 = 0.74 = 74 % — the mixture remains unsaturated, no fog forms.

Result

Humidity ratio of the mixture xM0.0167 kg/kg dry air
Mixing temperature tM26.8 °C
Relative humidity φM≈ 74 %
Total mass flow1.5 kg/s humid air
Calculation basis: Mollier h-x methodology for ideal humid air: x = 0.622·pD/(p−pD), h = 1.005·t + x·(2,501 + 1.86·t) kJ/kg dry air; saturation pressure from the Magnus formula; mass, water and enthalpy balances referred to dry air.

Technical content source: LV-Solved-Problems-Content 628d313247e7